Question

What is the length of the side of the rhombus whose diagnols are 12 cm and 16 cm​

Answer 1

Answer:

Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒  We know that the diagonals of rhombus bisect at right angles.

⇒  AO=  

2

16

​  

=8cm

⇒  BO=  

2

12

​  

=6cm

⇒  In right angled △AOB,

By using Pythagoras theorem,

⇒  AB  

2

=AO  

2

+BO  

2

 

⇒  AB  

2

=8  

2

+6  

2

 

⇒  AB  

2

=64+36

⇒  AB  

2

=100

⇒  AB=  

100

​  

 

⇒  AB=10cm

∴  Side of a rhombus is 10cm.

Step-by-step explanation:

Answer 2

Answer:

One diagonal is 16 and another 12 then half of both is 8 and 6 diagonal of rhombus bisect at 90 degree

By pythogaurus theorem

8^2+6^2=h^2

64+37=100

side =10