what is the linear acceleration( in m/s2) of the rope if the rope is pulled with a force of 30 N.
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Answer:
Here,
Mass of hollow cylinder (m) = 3kg
Radius ( r) = 40 cm
Force (F) = 30 N
Moment of inertia of hollow sphere about its axis of symmetry ( I) = mr²
= 3 × (0.4)² = 0.48 Kg.m²
Torque acting on cylinder by applied force = r× F
= 30 × 0.4 = 12N.m
Angular acceleration produced in cylinder ,
angular acceleration = torque /M.O.I
= 12/0.48 = 25 rad/s²
Linear acceleration = angular acceleration × radius
= 0.4 × 25 = 10 m/s²
Explanation:
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