Question

What is the longest pole that can be put in a room of dimensions l = 10 cm, b = 10 cm and h = 5 cm?

Answer 1

Step-by-step explanation:

the longest pole that can be put in a room will be equal to its diagonal:

Hence, longest length of pole

$longest \: length \: of \: pole = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } \\ = \sqrt{ {10}^{2} + {10}^{2} + {5}^{2} } \\ = \sqrt{ 100 + 100 + 25 } \\ = \sqrt{ 225 } \\ = 15 \: cm.$

Answer 2

Answer:

the longest pole that can be put in a room will be equal to its diagonal:

the longest pole that can be put in a room will be equal to its diagonal:Hence, longest length of pole

$[tex]\begin{gathered}longest \: length \: of \: pole = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } \\ = \sqrt{ {10}^{2} + {10}^{2} + {5}^{2} } \\ = \sqrt{ 100 + 100 + 25 } \\ = \sqrt{ 225 } \\ = 15 \: cm. \\ \end{gathered} </p><p>longestlengthofpole= </p><p>l$[/tex]

Step-by-step explanation:

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