English, asked by SRAdithya, 9 months ago

What is the lower limit of the electric face two charged
particles placed at a separation of 1cm in vacuum​

Answers

Answered by kaira199singh
0

Explanation:

Answer: Yes, there's a lower limit to the electric force between two particles placed at a separation of 1 cm, which is equal to the magnitude of force of repulsion between two electrons placed at a separation of 1 cm.

Answered by Anonymous
1

Explanation:

Virtuoso

Yes !! there is a lower limit to the electric force between 2 particles placed at a separation of 1 cm.

We know that force ( say F) between two charged particles ( having charges q and Q ) separated by a distance of r is given by :

F = kQq/r²

To find the lower limit we have to assume the charge on the both of the particles lowest possible ; And the quantum of charge is still the charge on an electron ( say e) .

=> lower limit of force in our case is :

F = ke²/r²

here r is 1cm = 0.01 m

k= 9×10^9 N-m²/C²

=>

F ( lowest possible) = 2.3×10^-24 N

______________

hope it helps !

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