What is the lowest essergy that a neutron can have
it, confined to move along the edge of an impenetrable
box of length 10^-14m
?
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0
Answer:
The particle energy takes on certain discrete values. It is usually said that a particle is in certain energy states.
E_n =\frac{n^2h^2}{8mL^2}E
n
=
8mL
2
n
2
h
2
We have conditions
n=1; L=10^{-14} m=1.67 \cdot 10^{-27}n=1;L=10
−14
m=1.67⋅10
−27
E_n =\frac{1^2\cdot 6.63*10^{-34}}{8\cdot 1.67 \cdot 10^{-27}\cdot 10^{-28}} =3.29 \cdot 10^{-13} (J)E
n
=
8⋅1.67⋅10
−27
⋅10
−28
1
2
⋅6.63∗10
−34
=3.29⋅10
−13
(J)
Answer is 1) 3.29x10^-13 (J)
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