Physics, asked by bhartiyaprincy, 1 month ago

What is the lowest essergy that a neutron can have
it, confined to move along the edge of an impenetrable
box of length 10^-14m
?​

Answers

Answered by kunal6214
0

Answer:

The particle energy takes on certain discrete values. It is usually said that a particle is in certain energy states.

E_n =\frac{n^2h^2}{8mL^2}E

n

=

8mL

2

n

2

h

2

We have conditions

n=1; L=10^{-14} m=1.67 \cdot 10^{-27}n=1;L=10

−14

m=1.67⋅10

−27

E_n =\frac{1^2\cdot 6.63*10^{-34}}{8\cdot 1.67 \cdot 10^{-27}\cdot 10^{-28}} =3.29 \cdot 10^{-13} (J)E

n

=

8⋅1.67⋅10

−27

⋅10

−28

1

2

⋅6.63∗10

−34

=3.29⋅10

−13

(J)

Answer is 1) 3.29x10^-13 (J)

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