What is the lowest number that must be added to 2000 so that the sum is divisible exactly by 10 12 16 and 18
Answers
Answer:
To find : The least number that must be added to 2000 so that the sum is divisible exactly by 10, 12, 16 and 18?
Solution :
We find the LCM of 10, 12, 16 and 18.
2 | 10 12 16 18
2 | 5 6 8 9
2 | 5 3 4 9
2 | 5 3 2 9
3 | 5 3 1 9
3 | 5 1 1 3
5 | 5 1 1 1
| 1 1 1 1
LCM(10,12,16,18)=2\times 2\times 2\times 2\times 3\times 3\times 5LCM(10,12,16,18)=2×2×2×2×3×3×5
LCM(10,12,16,18)=720LCM(10,12,16,18)=720
Now, Divide 2000 by 720
\frac{2000}{720}=2.77
720
2000
=2.77
The least number is 3.
So, 720\times 3=2160720×3=2160
The least number that must be added to 2000 so that the sum is divisible exactly by 10, 12, 16 and 18 is given by,
2160-2000=1602160−2000=160
Therefore, The required number that must be added to 2000 so that the sum is divisible exactly by 10, 12, 16 and 18 is 160.
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Answer:
1
Step-by-step explanation: