What is the lowest value of n that allows g orbitals to exist?
Explanation is required.
Answers
Answered by
12
Heya Bro☺☺
Here we go,
For n; the values of l are 0,1,…(n -1)
For n = 5; the values of l are 0,1,2,3,4
For l = 4; g subshell can exist. Hence lowest value of n = 5.
Hope this will help☺☺
Here we go,
For n; the values of l are 0,1,…(n -1)
For n = 5; the values of l are 0,1,2,3,4
For l = 4; g subshell can exist. Hence lowest value of n = 5.
Hope this will help☺☺
Answered by
15
Hey mate!
Here's your answer!!
Quantum numbers = the set of four number which gives a complete information about the electrons in an atom.
Here n = principal quantum number
As for any value ‘n’ of principal quantum number, the Azimuthal quantum number (l) can have a value from zero to (n – 1).
For n = 1 (K shell) has l = 0 (one subshell)
For n = 2 (L shell) has l= 0,1 (2 subshell)
For n = 3 (M shell) has l = 0,1,2 (3 subshell)
For n = 4 (N shell) has l = 0,1,2,3 (4 subshell)
For n = 5 (O shell) has l = 0,1,2,3,4 (5subshell)
∴ For l = 4, minimum value of n = 5.
✌ ✌ ✌
#⃣Be Brainly
Here's your answer!!
Quantum numbers = the set of four number which gives a complete information about the electrons in an atom.
Here n = principal quantum number
As for any value ‘n’ of principal quantum number, the Azimuthal quantum number (l) can have a value from zero to (n – 1).
For n = 1 (K shell) has l = 0 (one subshell)
For n = 2 (L shell) has l= 0,1 (2 subshell)
For n = 3 (M shell) has l = 0,1,2 (3 subshell)
For n = 4 (N shell) has l = 0,1,2,3 (4 subshell)
For n = 5 (O shell) has l = 0,1,2,3,4 (5subshell)
∴ For l = 4, minimum value of n = 5.
✌ ✌ ✌
#⃣Be Brainly
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