Question

What is the (m/M)% of sugar if 10 God sugar present in 90 g of water

Answer 1

Answer:

10gm

Explanation:

formula of m/M% =Mass of solute/Mass of solution×100

Here mass of solute i.e Sugar=10gm

mass of solvent i.e water=90gm

solute+solvent=solution

10g+90g =100g

m/M% = 10/100×100

=10gm