What is the magnetic field at a point 80 mm from a wire carrying current of 6A?
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Dear Student,
◆ Answer -
B = 15×10^-6 T
● Explaination -
# Given -
I = 6 A
x = 80 mm = 0.08 m
# Solution -
Magnetic field at a point x m away ftom the wire is given by -
B = μI / 2πx
Substitute values,
B = 4π×10^-7 × 6 / (2π × 0.08)
B = 15×10^-6 T
Hence, the magnetic field at a point is 15×0^-6 T.
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