what is the magnetic moment of Cr atom in its ground stage
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In its ground state, The electronic configuration of Chromium is 4s¹ 3d⁵.
So, the d-orbital has 5 unpaired electrons.
Magnetic moment = √(n)(n+2)
= √(5)(5+2)
= √(5x7)
= √(35)
= 5.91 Bohr magneton
So, the d-orbital has 5 unpaired electrons.
Magnetic moment = √(n)(n+2)
= √(5)(5+2)
= √(5x7)
= √(35)
= 5.91 Bohr magneton
sauravos26:
its root under 48
ya....sorry my bad....i'll edit the answer in a second.....i totally forgot about the unpaired electron in 4s sub shell'
yes it is under root 48, sorry for it .....i cannot find the edit link.
no problem , but thanks for the solution it gave me the idea how to slove it . thanks
welcome. im happy it was helpful
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