Question

What is the magnetomotive force in a 150-turn coil of wire with 2 a flowing through it?

Answer 1

Answer:

300 ampere-turns

Explanation:

MMF = nI = 150 × 2 = 300 ampere-turns

Answer 2

The magnetomotive force in a 150-turn coil of wire with 2 a flowing through it is 300 Ampere-turns.

Given:

Number of turns = 150

Current = 2A

To find:

Magnetomotive force = ?

Solution:

Magnetomotive Force:

It is analogous to the electromotive force and is one of the factor responsible to set up the flux. It generally equals to the number of turns which carry an electric current and has ampere-turns units.

Formula to be used:

Magnetomotive force = Number of turns × Current.

Magnetomotive force = 150 × 2

Magnetomotive force = 300 Ampere-turns.

Therefore, the magnetomotive force in a 150-turn coil of wire with 2 a flowing through it is 300 Ampere-turns.