What is the magnitude and direction of an electric field that exerts a 2.00 × 10−5 N upward force on a −1.75 μC charge?
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Explanation:
The force on an electric charge in an electric field is given by:
F=qE
Where the force and electric field are vectors. Since this is a one-dimensional problem, the direction can be specified by a plus or minus sign. Taking up to be positive, we have:
+2.00x10−5=−1.75x10−6E
E=−11.4N/C
Since the charge is negative, the field and force point in opposite directions.
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Answer:
10−5 N upward force on a −1.75 μC charge?
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