What is the magnitude and direction of the resultant of a pair of forces of: 10N at 60 degrees to 10N
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Answer:
The resultant of two force is given by F=
A
2
+B
2
+2ABcosθ
where, A & B are two vectors & θ is the angle between them.
Magnitude or resultant is
2×10
2
+2×100cos60
0
=10
3
N.
Whereas, the direction of the resultant vector is given by:
tanϕ =
A+Bcosθ
Bsinθ
=
10+10cos60
0
10sin60
0
=
3
1
⟹ϕ=30
0
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