Question

What Is The Magnitude And Direction Of Vectors I+J And I-J ?

Answer 1

for i+j

∣i+j∣=√[(1)^2+(1)^2]=√2

direction =tan-(1/1)=+45degrees

to the x-axis

for , i−j

∣i−j∣=√[(1)^2+(1)^2]=√2

direction =tan−(1/1)=

−45 degrees to the x-axis.

Answer 2

Given

 $\hat{i}+\hat{j}\\\\\hat{i}-\hat{j}$

Explanation:

for

$\hat{i}+\hat{j}\\\\\left | \hat{i}+\hat{j} \right |= \sqrt{1^2+1^2}= \sqrt{2}\\\\tan^-^1\left ( \frac{1}{1} \right )= +45^\circ\\\\\hat{i}-\hat{j}\\\\\left | \hat{i}+\hat{j} \right |= \sqrt{1^2+1^2}= \sqrt{2}\\\\\tan^-^1\left ( \frac{-1}{1} \right )= -45^\circ$

thus m, The magnitude is √2 for both the vectors

but the direction for $\hat{i}+\hat{j}$ is +45° to the x axis

and for $\hat{i}-\hat{j}$ is -45° to the x axis

#Learn more :

https://brainly.in/question/15521289