what is the magnitude of a force which produces of 7000pa while acting on a surface of area of cross-section 0.25m2
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Hey mate........ Here is the correct answer...force = 1750 N
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1
Answer:
Explanation:
Pressure=Force/area
P= 7000pascal
A=0.25m2
F=P*A
P= 7000*0.25
=1750newton
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