What is the magnitude of a forced which produces a pressure of 7000pa while acting on a surface of area of cross-section 0.25metre square
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Answered by
4
Explanation:
since pressure =force*area
herep=7000andarwa=0.25m²
so
7000=F*0.25
7000÷0.25=F
F=28000N
Answered by
4
Answer:
F= P/A
F= 7000/0.25
F= 28000N
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Explanation:
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