What is the magnitude of a point charge chosen so that the electric field 45 from the charge has magnitude 2.0 N/C
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r= 45, E = 2.0 N/C
w.k.t
E =F/Q
F=qQ/4π€r2
1/4π€=9 ×10^9
E =9×10^9q/R2
q=Er2/9×10^9
q=2×45×45/9×10^9
q=2×5×45×10^-9
q=450×10^-9 Coulomb
w.k.t
E =F/Q
F=qQ/4π€r2
1/4π€=9 ×10^9
E =9×10^9q/R2
q=Er2/9×10^9
q=2×45×45/9×10^9
q=2×5×45×10^-9
q=450×10^-9 Coulomb
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