What is the magnitude of a point charge chosen so that the electric field 50 cm away has magnitude 2.0 N/C?
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let magnitude of charge be Q. so,magnitude of electric field (E) at a distance r = 0.5m away in given by: - E KQr2 , which gives: Q = Er2k = 2 × (0.5)29
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Electricity is useful for Many things that occur in the physical world are known as janhana( janahana means people) with the electric charge The electric charge was released in the light of the sky power of lightning electricity used as a source of energy, etc. Before the development of the Maxwell's equation, it is considered to be the first thing in the form of a physical phenomenon of energy.
:):)
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