Question

What is the magnitude of force required in newton's in to produce a pressure of 27500 pa on area of 270cm2?

Answer 1

Answer:

742.5 N

Explanation:

As per the provided information in the given question, we have :

• Pressure (P) = 27500 Pa
• Area (A) = 270 cm²

We are asked to calculate magnitude of force required (in N).

In order to calculate magnitude of force required (in N), firstly we need to convert 270 cm² in m².

$\longmapsto \rm { 1 \; cm^2 = \dfrac{1}{10000} \; m^2 }$

$\longmapsto \rm { 270\; cm^2 = \dfrac{270}{10000} \; m^2 }$

$\longmapsto \rm { 270 \; cm^2 = \dfrac{27}{1000} \; m^2 }$

$\longmapsto \bf{ 270 \; cm^2 = 0.027 \; m^2 }$

Now, we'll find the force required. For that, we'll using the formula of pressure. As we know that,

$\longmapsto\bf { P = \dfrac{F}{A} }$

• F denotes force
• P denotes pressure
• A denotes area

$\longmapsto\rm { P \times A = F }$

$\longmapsto\rm { 27500 \; Pa \times \dfrac{27}{1000} \; m^2 = F }$

$\longmapsto\rm { 27500 \; \dfrac{N}{m^2} \times \dfrac{27}{1000} \; m^2 = F }$

$\longmapsto\rm { 275 \; \dfrac{N}{\cancel{m^2}} \times \dfrac{27}{10} \; \cancel{m^2 } = F }$

$\longmapsto\rm { \dfrac{7425}{10 } \; N= F }$

$\longmapsto\bf { 742.5 \; N= F }$

∴ Force required is 742.5 N.

More Information :

• Pressure is defined as force per unit area.
• Its SI unit is Pa.
• Pa is equivalent to N/m².
• Force is defined as push or pull which tends the position, shape, speed of the object.
• SI unit of force is Newton.
• Newton is denoted by N.
• Force is also the product of mass and acceleration, i.e Force = Mass × Acceleration

Answer 2

Answer:-

• Pressure=27500Pa
• Area=270cm^2=0.027m^2

We know that

$\boxed{\sf Pressure=\dfrac{Force}{Area}}$

$\\ \sf\longmapsto Force=Pressure\times Area$

$\\ \sf\longmapsto Force=27500\times 0.027$

$\\ \sf\longmapsto Force=742.5N$