Question

What is the magnitude of force required in newton to produce pressure of 27500pa on an area of 200cm?

Answer 1

P=27500Pa

A=200×10^-2 m^2

w.k.t,

P=F/A

Therefore,

=27500/200×10^-2

=13750N is the force required.

Answer 2

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

Force (f) = ?

Area (a) = 200 cm^2 = 200/10000 m^2

Pressure (p) = 27500 pa

Now , p= f/a

Therefore F = P* A = 27500*200/10000 = 550 n