Question

What is the magnitude of magnetic force per unit length of a wire carrying a current of 5A and making an angle of 30° with the direction of uniform magnetic field of 0.1 Tesla ?
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Answer 1

Answer:

Angle between the wire and magnetic field, Ω¸ = 30°. Hence, the magnetic force per unit length on the wire is 0.6 N m-1.

Answer 2

Answer:

The magnitude of magnetic force per unit length of the wire is 0.25 N /m

Explanation:

Given:

Current is 5A

Angle between current and magnetic field is 30 degree

Direction of uniform magnetic field is 0.1 tesla

To find: The magnitude of magnetic force per unit length of a wire.

Formula used: The magnetic force F = ILBsinθ

Solution:

Magnetic force:

The attractive or repulsive force that exists between the poles of a magnet and electrically charged moving particles is known as magnetic force. As a result, it is a result of electromagnetic forces.

In a magnetic field, a conductor carrying current faces magnetic forces. Fleming's Left-Hand Rule signifies the magnetic forces' direction

Formula

F = ILBsinθ

F is the magnetic force.

I is current.

l is the length of a straight conductor

B is the uniform magnetic field

θ is the angle between I and B.

Given

Current I = 5A

Uniform magnetic field = 0.1 Tesla

Angle θ = 30 degree

We know that

Magnetic Force F = IB lsinθ

       $\frac{F}{l}$ = I B sinθ

   ⇒ $\frac{F}{l}$ = 5 × 0.1 × sin30

  ⇒ $\frac{F}{l}$ = 5 × 0.1 × $\frac{1}{2}$

   ⇒ $\frac{F}{l}$ = 0.25 N /m

Force per unit length of a wire is 0.25N/m

Final answer:

The magnitude of magnetic force per unit length of the wire is 0.25 N /m

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