Question

What is the magnitude of the acceleration of a speck of clay on the edge of a potter’s wheel turning at 45 rpm(revolutions per minute)if its diameter is 30cm?

Answer 1

Answer:

acceleration of the point at a distance 'r' from the center of rotation is given by

a = r * alpha

alpha - angular acceleration

Here r = 0.35/2 m

42 rpm = (42 * 2 pi) / 60

a = r * alpha

a = 0.175 * 4.4

a = 0.77 m/s^2

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