What is the magnitude of the average force applied by a tennis racquet to a 58 g tennis ball during service if the average acceleration of the racquet is 1.2 x 10¹ m/s²?
Answers
Answered by
1
Explanation:
The change in momentum
Δp=m(v
f
−v
i
)
=0.150(60−(−40))
=0.150×100=15Ns
Thus, F=
Δt
ΔP
=
5×10
−3
15
=3×10
3
N
Similar questions