Question

what is the magnitude of the electric field at a field point 2.0 m from a point charge q = 4.0 nc​

Answer 1

what is the magnitude of the electric field at a field point 2.0 m from a point charge q = 4.0 nc

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Answer 2

To find:

Magnitude of electrostatic field intensity 2 metres away from a 4 nC charge ?

Calculation:

The general expression of electrostatic field intensity at a certain distance from a point charge as derived from GAUSS' LAW is :

$\boxed{ \bold{E = \dfrac{1}{4\pi \epsilon_{0} } \bigg ( \dfrac{q}{ {r}^{2} } \bigg)}}$

Putting the available values in SI unit :

$\sf \implies \: E = 9 \times {10}^{9} \times \bigg \{\dfrac{4 \times {10}^{ - 9} }{ {(2)}^{2} } \bigg \}$

$\sf \implies \: E = 9 \times \bigg \{\dfrac{4 }{ 4} \bigg \}$

$\sf \implies \: E = 9 \: N/C$

So, the electrostatic field intensity at the specified distance is 9 N/C.