Question

what is the magnitude of the electric field in a parallel apparatus whose plates are 5mm apart and have a potential deffernce of 300v​

Answer 1

Explanation:

Electric field E = V/d, where V is potential difference, and d is distance between the two plates.

so, here E= 100 V/1mm = 100/(10^-3)=100x10^3=10^5 (Volt/m)

So force on a electron in electric field is F= E.q = (10^5)x(1.6x10^-19) Newton