Question

what is the magnitude of the gradient of the function f(x,y,z)=x^2+3y^2+3z at the point(1,-1,2)

Answer 1

Step-by-step explanation:

the for for magnitude is =√(x^2+y^2+z^2)

so the answer is

|f(x,y,z)|=√(x^2+(3y)^2+(3z)^2)

|f(1,-1,2)|=√((1)^2+(3(-1))^2+(3(2))^2)

=√(1+3+12)

=√(16)

=4

there fore the magnitude of the given gradient is=4