Question

what is the magnitude of the gravitation force between the earth and a 1kg object on its surface ?(Mass of the earth is 6*10^24kg and radius of the earth is 6.4*10^6m).

class 9, chapter no 10, page no 143.

Answer 1

9.770 N .

Explanation:

Given m1 = 1 kg

m2 = 6 × 10²⁴ kg

R = 6.4 × 10⁶ m

F = ?

we know that

F = $\huge\frac{Gm1m2}{r²}$

$F = \frac{6.67 \times 10 {}^{ - 11} \times 1 \times 6 \times 10 {}^{24} }{(6.4 \times 10 {}^{6} ) {}^{2} }$

= 9.770 N . ans

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