Question

What is the magnitude of the gravitational accelaertion of the earth of object on itssurface? (Mass of the earth is 6 x 1024 kg andradius of the earth is 6.4 x 106m).A8.83 m/s2B9.8 m/s2C2.83 m/​

Answer 1

We know gravitation force F=

R

2

GMm

=

(6.4×10

6

)

2

6.67×10

−11

×6×10

24 ×1

=9.8N

Where M = mass of the earth, m = mass of the object and R = radius of earth

Answer 2

Here is your answer ↓

Given that,

Mass of the Earth=6*$10^{24}$

Mass of the object=1 kg

Radius of the Earth=6.4*$10^{6}$

Force of gravitation between Earth and the object will be

F=GMm/$R^{2}$

F=$\frac{6.67*10^{-11}*6*10^{24}*1 }{(6.4*10^{6})^2 }$

F=9.77N

∴ F=9.8 N