Question

What is the magnitude of the gravitational force between the
earth and a 1 kg object on its surface? (Mass of the earth is
6 x 1024 kg and radius of the earth is 6.4 x 106 m.)
ond+h​

Answer 1

Answer:

F=GMm/R²

m=1 kg

M= 6*1024 kg

R=6.4*106 m

G=6.67*10–¹¹

F= 6.67*10–¹¹*6*1024*1/(6.4*106)²

=9.8 N

Answer 2

Answer:

Mass of Earth, M = 6 × 10^24 kg

Mass of object, m = 1 kg

Universal gravitational constant,

G = 6.7 × 10^−11 Nm^2 kg^−2

r = radius of the Earth (R) ( ob. is on the surface of earth)

r = R = 6.4 × 10^6 m

Therefore, the gravitational force

F = GMm / r^2

= (6.7 × 10^-7 × 6 × 10^24 × 1)/ (6.4 ×10^4)^2

= 9.8 N