Question

what is the magnitude of the gravitational force between the earth and 10 kg object on its surface(mass of the earth=6×10^24) and radius of earth is 6.4×10^6, G=6.7×10^-11 Nm^2 kg​

Answer 1

Answer:

The magnitude of gravitational force is calculated by using the formula : F = G × m 1 × m 2 r 2 F=G×m1×m2r2 Now Gravitational constant G = 6.7 × 10 − 11 N m 2 / K g 2 G=6.7×10-11Nm2/Kg2 Mass of earth m 1 = 6 × 10 24 k g m1=6×1024kg Mass of object m 2 = 1 k g m2=1kg And , Distance between center r=Radius of earth of earth and object = 6.4 × 10 6 m =6.4×106m Now,Putting these values in the above formula ,we get Read more on Sarthaks.com - https://www.sarthaks.com/1165458/what-magnitude-gravitational-force-between-earth-object-surface-mass-earth-6xx10-radiusof earth of earth and object = 6.4 × 10 6 m =6.4×106m Now,Putting these values in the above formula ,we get F = 6.7 × 10 − 11 × 6 × 10 24 × 1 ( 6.4 × 10 6 ) 2 F=6.7×10-11×6×1024×1(6.4×106)2 or F= 9.8 N Thus the magnitude of gravitational force between the earth and a 1 kg objective on its surface is 9.8 Newton