Question

What is the magnitude of the gravitational force between the earth and a 1 kg
object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is
6.4 × 106m.)

Answer 1

Answer:

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1 0 24 10^{24} 1024 kg and radius of the earth is 6.4 × 1 0 6 10^6 106 m). This shows that Earth exerts a force of 9.8 N on a body of mass 1 kg.

Answer 2

Answer:

We know gravitation force F=

$\frac{GMm}{R ^{2} } = \\ \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 1}{(6.4 \times {10}^{6})^{2} } = 9.8 \: n$

Where M = mass of the earth, m = mass of the object and R = radius of earth

Explanation:

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