Question

WHAT is the magnitude of the gravitational force between the earth and a 1 kg object on its surface?
(Mass of the earth is
$6 \times {10}^{24}$
and radius of earth is
$6.4 \times {10}^{6}$
​

Answer 1

Answer:

Step-by-step Explanation:

Given : Mass of earth

$m = 6 \times {10}^{24}$

Mass of object m=1 kg

Radius of earth R=6.4×${10}^{6}$

Force of gravitation between them,

$F= GMm/ {R}^{2}$

$F=(6.67 \times {10}^{ - 11} \times( 6 \times {10}^{24}) \times 1/(6.4 \times {10}^{6})^{2} = 9.77N$

Your Question Ans is 9.77 N

Note: N is the sign of Newton

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