Physics, asked by vineetkaur6863, 1 year ago

what is the magnitude of the gravitational force between the earth and a 1 kg object on its surface(M=6 × 10^24 kg and R= 6.4 × 10^6m)

Answers

Answered by TheEdward
0
Hey pal check out the answer :)
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Answered by Anonymous
0

_/\_ Hello mate__ here is your answer -

Mass of Earth, M = 6 × 10^24 kg

Mass of object, m = 1 kg

Universal gravitational constant,

G = 6.7 × 10^−11 Nm^2 kg^−2

r = radius of the Earth (R) ( ob. is on the surface of earth)

r = R = 6.4 × 10^6 m

Therefore, the gravitational force

F = GMm / r^2

=(6.7×10^-7×6×10^24 ×1)/(6.4×10^4)^2

= 9.8 N

I hope, this will help you.☺

Thank you______❤

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