Question

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 x 1024 kg and radius of the earth is 6.4 x 106 m.)

Answer 1

Solution of your question is given in the attachment.

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Now, let's see the related topics ;

$\bf Gravitational \: force$ : The force if attraction between two particles towards the centre of the earth, is called gravitational force.

$\bf Universal \: Law \: of \: Gravitation$ : The gravitational force of attraction between any two particles is directly proportional to the product of the masses of the particles and is inversely proportional to the square of the distance between the particles.

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Answer 2

Dear Student,

◆ Answer -

F = 9.77 N

● Explanation -

# Given -

M = 6×10^24 kg

m = 1 kg

R = 6.4×10^6 m

# Solution -

Gravitational force between earth and the object is given by -

F = GMm/R²

F = 6.67×10^-11 × 6x10^24 × 1 / (6.4x10^6)²

F = 9.77 N

Therefore, gravitational force between the earth and an object is 9.77 N.

Hope this helps you...