Question

What is the magnitude of the gravitational force between the earth and a 1Kg object on its surface? (Mass of the earth is 6×10^24 Kg and radius of the earth is 6.4×10^6 m.)

Answer 1

Solution of your question is given in the attachment.

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Now, let's see the related topics ;

$\bf Gravitational \: force$ : The force if attraction between two particles towards the centre of the earth, is called gravitational force.

$\bf Universal \: Law \: of \: Gravitation$ : The gravitational force of attraction between any two particles is directly proportional to the product of the masses of the particles and is inversely proportional to the square of the distance between the particles.

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Thanks for the question !

Answer 2

Hello mate__ here is your answer --

Mass of Earth, M = 6 × 10^24 kg

Mass of object, m = 1 kg

Universal gravitational constant,

G = 6.7 × 10^−11 Nm^2 kg^−2

r = radius of the Earth (R) ( ob. is on the surface of earth)

r = R = 6.4 × 10^6 m

Therefore, the gravitational force

F = GMm / r^2

= (6.7 × 10^-7 × 6 × 10^24 × 1)/ (6.4 ×10^4)^2

= 9.8 N

I hope, this will help you.☺

Thank you______❤

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