What is the magnitude of the total force on a driver by the racing car he operates as it accelerates
horizontally along a straight line from rest to 60 m/s in 8.0s? (mass of driver = 80 kg)
(A) 0.06 KN
(B) 0.78 KN
(C) 1.4 KN
(D) 1.0KN
Answers
Answered by
9
Answer:
Answer of your question is 0.06kN
Answered by
23
Answer:
Option D) 1KN.
Explanation:
Since, the initial velocity of the car given in the question is zero and the final velocity is given as 60 m/s in the time of 0.8 seconds. So, on applying Newton's first law of motion v=u+at.
60=0+a*8 on solving we will get the value of acceleration to be 15/2 m/s^2. So, the force on a driver by the racing car will be F=ma or F=80*15/2 which on solving we will get the force exerted in the horizontal to be 600N and the vertical exertion of the force is 80*10=800N.
So, the magnitude of total force is √(600^2 +800^2) which will be 1000N or 1KN.
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