Physics, asked by vishwassoni704, 10 months ago

what is the magnitude of the vector 3 î -4j(cap) + √4k

Answers

Answered by ReRepeater
2

Explanation:

These are orthogonal vectors

Magnitude |v| = √(9 + 16+ 4 )

                       =√29

Answered by rajnitiwari192003
6

Answer:

GIVEN:-

vector = 3î -4 j(cap) + √4 k(cap)

vector = 3î -4 j(cap) + 2k(cap)

Ax = 3

Ay = 4

Az = 2

TI FIND:-

magnitude of vector

FORMULA :-

magnitude = √(Ax)²+(Ay)²+(Az)²

SOLUTION:-

magnitude = √(3)²+(4)²+(2)²

= √9+16+4

Magnitude of vector= √29 = 5.38

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