what is the magnitude of the vector 3 î -4j(cap) + √4k
Answers
Answered by
2
Explanation:
These are orthogonal vectors
Magnitude |v| = √(9 + 16+ 4 )
=√29
Answered by
6
Answer:
GIVEN:-
vector = 3î -4 j(cap) + √4 k(cap)
vector = 3î -4 j(cap) + 2k(cap)
Ax = 3
Ay = 4
Az = 2
TI FIND:-
magnitude of vector
FORMULA :-
magnitude = √(Ax)²+(Ay)²+(Az)²
SOLUTION:-
magnitude = √(3)²+(4)²+(2)²
= √9+16+4
Magnitude of vector= √29 = 5.38
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