Question

What is the magnitude of thrust required in newton to produce a pressure of 26500Pa on an area of 100 cm² ?​

Answer 1

Given :

• Pressure, P = 26500 Pa
• area on which force is applied, A = 100 cm²

To find :

• Magnitude of the thrust required, F = ?

Formulae required :

• Relation between Thrust (F) , Pressure (P) and Area (A)

      P = F / A

• The force acting perpendicular on a surface is known as Thrust.
• S.I. unit of thrust is Newton (N)
• 1 Newton = 1 kg ms⁻²
• Dimensional formula of Thrust is given by [ M L T⁻² ]

Calculation :

Converting Area given in cm² into m²

→ A = 100 cm²

→ A = 100 × ( 1 / 100 )²  m²

→ A = 0.01 m²

Using formula

→ P = F / A

→ F = P × A

→ F = 26500 × 0.01

→ F = 265 N

therefore,

The thrust required  ( In Newton ) to produce a pressure of 26500 Pa on an Area of 100 cm² is 265 Newtons.

Answer 2

please refer above image for answer and explanation