What is the magnitude of thrust required in newton to produce a pressure of 26500 Pa on an area of 100 cm² ?
Answers
Answer:
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Explanation:
Given :
Pressure, P = 26500 Pa
area on which force is applied, A = 100 cm²
To find :
Magnitude of the thrust required, F = ?
Formulae required :
Relation between Thrust (F) , Pressure (P) and Area (A)
P = F / A
The force acting perpendicular on a surface is known as Thrust.
S.I. unit of thrust is Newton (N)
1 Newton = 1 kg ms⁻²
Dimensional formula of Thrust is given by [ M L T⁻² ]
Calculation :
Converting Area given in cm² into m²
→ A = 100 cm²
→ A = 100 × ( 1 / 100 )² m²
→ A = 0.01 m²
Using formula
→ P = F / A
→ F = P × A
→ F = 26500 × 0.01
→ F = 265 N
therefore,
The thrust required ( In Newton ) to produce a pressure of 26500 Pa on an Area of 100 cm² is 265 Newtons.
Answer:
265
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