Question

What is the magnitude of thrust required in newton to produce a pressure of 35000 Pa on an area of 500 cm2?​

Answer 1

Answer:

1,750 N

Step-by-step explanation:

Pressure=35,000 Pa or N/m

Area= 500 cm^2

If P(Pressure )=F(Thrust)/Area,

Then, F= P x A

A=500 cm^2 But we need it in m^2.

So, we simply divide it by 10,000.

500/10,000 = 0.05 m^2

F=P x A

=35000 x 0.05

=1750 N

Hope it helps...