Science, asked by rajkumar8675, 10 months ago

what is the magnitude of vector 2i^-3j^+√3k^?

Answers

Answered by prachi6133

2

the magnitude of vector is

= under root ... 2^2 + 3^2 + root 3 ^2

= under root .. 4+9+3

= under root... 11

Answered by MissNerds

3

Answer: 4

Magnitude = Sqrt 2²+(-3)²+(√3)²

= Sqrt 4+9+3

= Sqrt 16

= 4

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