What is the magnitude of your total displacement if you have traveled due west with a speed of 23 m/s for 155 s , then due south at 12 m/s for 225 s? What is the direction of your total displacement in part A.
Answers
Answer:
magnitude? Easy, they are at right triangles.
magnitude=sqrt(23*125)^2 + (12*255)^2 )
angle W of S is arctan((W/S) or
arctan ((23*125)^2/(12*255)^2 )
Answer:
The total displacement is 36.5° south of west.
Explanation:
To calculate the total displacement of an object, we need to determine the magnitude and direction of its displacement in each component. In this problem, the object travels due west with a speed of 23 m/s for 155 s and then due south at 12 m/s for 225 s.
To calculate the magnitude of the total displacement, we can use the Pythagorean theorem. The displacement due west can be calculated as:
dwest = vwest × t = 23 m/s × 155 s = 3565 m
Similarly, the displacement due south can be calculated as:
dsouth = vsouth × t = 12 m/s × 225 s = 2700 m
Now, using the Pythagorean theorem, the magnitude of the total displacement can be calculated as:
dtotal = sqrt(dwest^2 + dsouth^2) = sqrt(3565^2 + 2700^2) = 4550 m
Therefore, the magnitude of the total displacement is 4550 meters.
To determine the direction of the total displacement, we can use trigonometry. The displacement due west and due south form a right triangle, and the angle between the displacement and the west direction can be calculated as:
tanθ = dsouth / dwest = 2700 m / 3565 m
θ = tan^-1(2700 / 3565) = 36.5°
Therefore, the direction of the total displacement is 36.5° south of west.
Learn more about displacement :
https://brainly.in/question/25716444
#SPJ2