Question

What is the magnitude or length of vector î+2^j + 2√2^k​

Answer 1

Answer:

$\rm \sqrt{13}$

Step-by-step explanation:

Any vector of the form :

$\rm a \hat{i} + b \hat{j} + c \hat{k}$

Then the magnitude is

$\rm \sqrt{a^2+ b^2 + c^2}$

$\rm \large \underline{Solution:}$

$\rm \vec{A} = \hat{i} + 2 \hat{j} + 2 \sqrt{2} \hat{k}$

$\rm | \vec{A}| = \sqrt{ {1}^{2} + {2}^{2} + ({2 \sqrt{2} } )^{2} }$

$\rm |\vec{A} |= \sqrt{1+4 + 8}$

$\rm |\vec{A} |= \sqrt{13}$