Question

What is the mass grams that are in 2.57 × 10¹⁵ molecules of CO?

Answer 1

Answer is given in the pic.

Answer 2

Given:

Molecules of $\[CO = 2.57 \times {10^{15}}\]$

To Find:

Mass grams in 2.57 × 10¹⁵ molecules of CO

Solution:

Number of moles can be given as:

$\[Moles = \frac{{No.\,\,of\,molecules}}{{Avogadro\,number}}\]$

Therefore, the number of moles in  2.57 × 10¹⁵ molecules of CO can be given as:

$\[Moles = \frac{{2.57 \times {{10}^{15}}}}{{6.023 \times {{10}^{23}}}}\]$

$\[Moles = 4.267 \times {10^{ - 9}}\]$

Number of moles can also be given as:

$\[No.\,of\,moles = \frac{{Mass}}{{Molar\,mass}}\]$

Therefore, mass grams in 2.57 × 10¹⁵ molecules of CO

$\[Mass = 4.267 \times {10^{ - 9}} \times 28\]$

$\[Mass = 119.476 \times {10^{ - 9}}g\]$

Hence, the mass grams in 2.57 × 10¹⁵ molecules of CO are $\[119.476 \times {10^{ - 9}}g\]$.