Question

What is the mass in grams of 0.0287 mol of sucrose

Answer 1

Answer:

Given:

Moles of C12 H22 O11 = 0.0287.

Molar mass of C12 H22 011 = 12(12) + 1(22) + 16(11)

                                                = 144 + 22 + 176

                                                = 342g.

Mass in grams = ?

Solution:

Mass in grams of Sucrose = moles*molar mass.

                                             = 0.0287*342

                                             = 9.82g.

Answer 2

Given:

The no of moles of sucrose = 0.0287

To Find:

The mass of sucrose.

Calculation:

- The formula of sucrose is C12H22O11.

- The molar mass of sucrose = 12 × 12 + 22 × 1 + 11 × 16

⇒ M.wt = 144 + 22 + 176

⇒ M.wt = 342 gm/mol

- The mass of sucrose = No of moles × Molar mass

⇒ M = 0.0287 × 342

⇒ M = 9.8154 gm

- So, the mass of sucrose in 0.0287 moles is 9.8154 gm.