What is the mass, in grams, of potassium in 12.5 g of K2Cr2O7 (molar mass = 294 g/mol)? (K = 39, O = 16, Cr = 52)
a) 1.66 g
b) 0.0424 g
c) 8.80 g
d) 3.32 g
Answers
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Option d)3.32 g is correct.
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Answered by
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Answer:
option D is the correct one
Explanation:
Let us first write the formula for finding the overall percentage of K in K2Cr207
The molar mass of the compound is= 294
Percentage of K in compound would be
= 39 x 2 / 294 x 100 = 26.53%
So if we are now given 12.5 grams of the compound then, using the same principle we see that
K = 26.53/100 x 12.5
K = 3.316 grams
Rounding it off
K = 3.32 g
Hence among the fout options given, option D is the correct one
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