Question

What is the mass/mass % of a solution made by mixing 100 grams of sugar in 900 ml of water.​

Answer 1

Answer:

\Large A = P \left(1+\frac{r}{100}\right)^{n} => 7986 = 6000 \left(1+\frac{10}{100}\right)^{n} \)

=> \( \Large \frac{7986}{6000}=\frac{11}{10}^{n} => \frac{1331}{1000}= \left(\frac{11}{10}\right)^{n} => n = 3 years \)

Answer 2

$\huge \bigstar { \underline{ \mathtt{ \red{A}{ \pink{n}{ \color{blue}{s}{ \color{gold}{w}{ \color{aqua}{e}{ \color{lime}{r}}}}}}}}}★$

Rearranging the equation for concentration allows the mass of solute to be calculated:

• mass of solute in g = concentration in g/dm 3 × volume in dm 3
• A solution of sodium chloride has a concentration of 10 g/dm 3. ...
• mass of solute in g = concentration in g/dm 3 × volume in dm 3
• = 10 g/dm 3 × 2 dm 3

Hope it's helpful to you ☺️❣️