what is the mass of 0.2 mole of number of particals in 23 grams of na atom
atomic mass of na=32u
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Answer:
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Answer:
4.6 gms.
Explanation:
There are 6.02*10^23 atoms in each mole (Avagadro no.) That is x moles * avagadro no. According to that, in 23 grams of sodium we have 6.02*10^23 atoms of Na.
Atomic Mass of Na is 23 u.
so, the required mass of Number of particles in 23 gms = 0.2 × 23 = 4.6 g.
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