What is the mass of 1.20×10*24 atoms of sodium
Answers
Answer:
Number of atoms of sodium (Na) = 1.20 X 10²⁴ atoms
Avogadro's number (NA) = 6.022 X 10²³ atoms
Mass of Na = ??
Explanation:
As we know that mass can be calculated by formula
No. of Moles Na = mass of Na/ Molecular mass of Na
therefore, for calculating mass of Na we need number of moles of Na,
1 mol of Na contains = 6.022 X 10²³ atoms
x mol of Na contains = 1.20 X 10²⁴ atoms
No. of moles of Na = (1.20 X 10²⁴ atoms X 1 mol of Na ) / 6.022 X 10²³ atoms
No. of moles of Na = 1.99 moles
1.20 X 10²⁴ atoms of Na contains 1.99 moles of Na
Now for mass,
No. of Moles Na = mass of Na/ Molecular mass of Na
Molecular mass of Na = 23 g/ mol
Mass of Na = 23 g/ mol X 1.99 mol
Mass of Na = 45.77 grams
Hope it helps U !!
Given:
1.20 × 10²⁴ atoms of Sodium
To Find:
Mass of 1.20 × 10²⁴ atoms of Sodium
Solution:
We know that,
1 mole of any substance contains 6.022 x 10²³ atoms
Given that,
1.20 × 10²⁴ atoms of Sodium
Mathematically,
Therefore,
By cross-multiplication,
We get,
On further simplification,
We get,
Hence,
1.20 × 10²⁴ atoms of Sodium contains 1.99 moles of Sodium
We know that,
Mass of Sodium = 23 u
Hence,
1 mole of Sodium has mass of 23 g
We know that,
Here,
- n = Number of moles
- m = mass of Sodium
- M = Molecular mass of Sodium
According to the Question,
We are asked to find the mass of 1.20 × 10²⁴ atoms of Sodium
So, we must find Mass of Sodium (m)
Hence,
We found out that,
- n = 1.99 moles
We know that,
- M = 23 g
Substituting the values,
We get,
Therefore,
Mass of 1.20 × 10²⁴ atoms of Sodium is 45.77 grams