Question

What is the mass of 1.20 x 1025 atoms of sulfur

Answer 1

Answer:

1230

Explanation:

1.20 ×1025=1230

this is the explanation of this mass question

Answer 2

Answer:

The mass of 1.20 × 10²⁵ atoms of sulphur is 637.44g.

Explanation:

Given,

Total number of sulphur atoms = 1.20 × 10²⁵

Mass of 1.20 × 10²⁵ sulphur atoms = ?

Firstly, we need to calculate the number of moles present in 1.20 × 10²⁵ atoms of sulphur.

As we know,

• In 1 mole there are 6.022 × 10²³ atoms present.
• 1 mole = 6.022 × 10²³ atoms
• $1 atom = \frac{1}{6.022 \times 10^{23} }$ mol

So,

• $1.20 \times 10^{25} atoms= \frac{1.20 \times 10^{25} }{6.022 \times 10^{23} } mol$  = 19.92 mol

Now,

Molar mass of sulphur, M  = 32 g/mol

Number of moles of 1.20 × 10²⁵ sulphur atoms, n = 19.92

Therefore,

• The mass of sulphur atoms, m, can be calculated by the equation given below
• $n = \frac{m}{M}$

Here,

n = number of moles

m = mass of sulphur atoms

M = molar mass of sulphur

So,

• $19.92 = \frac{m}{32}$
• m = 19.92 × 32
• m = 637.44 g

RESULT: Mass of 1.20 × 10²⁵ atoms of sulphur is 637.44g.